Solving Proportions
Tara Lint
MAT 222 Week 1 Assignment
Instructor: James Segala
August 18, 2013

Solving Proportions
Proportions exist in the real world. For example, in finding out the price of a unit, or the population of a specific species. The first problem that we are working with states that “. Bear population. To estimate the size of the bear population on the Keweenaw Peninsula, conservationists captured, tagged, and released 50 bears. One year later, a random sample of 100 bears included only 2 tagged bears.What is the conservationist’s estimate of the size of the bear population?(Dugolpolski, 2012)

In reading over the “Bear Population” #56 on page 437 (Dugolpolski, 2012), the concept of proportions allow the assumption that the ratio of originally tagged bears to the whole population is equal to the ratio of recaptured tagged bears to the size of the sample. The estimated solution, variables will be defined and rules for solving proportions are used. The ratio of originally tagged bears to the whole population is 50/x. The ratio of recaptured tagged bears to the sample size is 2/100. 50=2This is the proportion set up and ready to solve. This is the step where we will cross multiply. x 100at this point. The extremes are 100 and 50. The means are x and 2 100(50)=2x

50002=2x2 Divide both sides by 2
X=2500The bear population of Keweenaw Peninsula is estimated to be around 2500.

For the second problem of this assignment the equation must be solved for y. Therefore, by continuing proportions, a single ratio (fraction) exist on both sides of the equal sign. Therefore, it is a proportion, which is solved by cross multiplying the extreme means.

So in this problem we are working problem #10 on page 444 (Dugolpolski, 2012). y-1x+3=-34 The original equation
y-1=-3
x+3 4
4(y-1)=-3(x+3)The result of cross multiplying
4y-4=-3x-9Distribute 4 on the left side and -3 on the right side 4y-4+4=-x+3+4Add 4 to both sides and reduce to...

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Solving Proportions
Jubenal Garcia
MAT222: Intermediate Algebra (GSQ1433A)
Instructor Linda Seeger
August 19, 2014
Solving Proportions
This week I learned about solving proportions. Rightfully so, on this assignment I have to prove or show what I’ve learned and retained by solving two problems. In this essay I will attempt to solve two problems from our textbook, the first one is problem 56 located on page 437 and the second one is problem 10 located on page 444 of our Elementary and Intermediate Algebra textbook. During this process I will incorporate the four math vocabulary words required, which are extraneous, proportion, cross multiply, and extreme-means which will be in bold.
Problem number 56 located on page 437 states and asks the following about bear population. “To estimate the size of the bear population on the Keweenaw Peninsula, conservationist captured, tagged, and released 50 bears. One year later, random sample of 100 bears included only 2 tagged bears. What is the conservationist’s estimate of the size of the bear population?” (Dogupolski, 2012). Since this is a ratio equation I will use b for the variable, b equaling the bear population which is what we need to find.
The first thing I did was to set up the two ratios, place the b for the variable which equals the bear population in this proportion. Then I cross multiply the extreme-means property as shown below.
2*b=100*50
2b=5000
Because...

...Real world applications
XXX
MAT126: Survey of Mathematical Methods
Instructor: XXX
May 20, 2012
In this assignment I would like to talk about arithmetic sequences and geometric sequences and want to give an example each how to calculate with those sequences. First I want to give a short definition of each sequence.
“An arithmetic sequence is a sequence of numbers in which each succeeding term differs from the preceding term by the same amount. This amount is known as the common difference.” (Bluman, A. G. 2500, page 221)
An example for an arithmetic sequence is:
1, 3, 5, 7, 9, 11, … (The common difference is 2. (Bluman, A. G. 2500, page 221)
“A geometric sequence is a sequence of terms in which each term after the first term is obtained by multiplying the preceding term by a nonzero number. This number is called the common ratio.” (Bluman, A. G. 2005, p. 225) Here you can see that there is always added 2.
1 + 2 = 3; 3 + 2 = 5; 5 + 2 = 7; 7 + 2 = 9; …
An example for a geometric sequence is:
2, 10, 50, 250, 1250, … (The common ratio is r = 5 (Bluman, A. G. 2005, p. 225)
Here you can see that the 2 is multiplied by 5, which is 10. Then the 10 is also multiplied by 5, which is 50 and so on.
2 x 5 = 10; 10 x 5 = 50; 50 x 5 = 250; 250 x 5 = 1250; …
In this assignment I have solved two exercises, one referring to arithmetic sequences and one referring to geometric sequences....

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Assignment1 – Week1MAT222Assignment1 – Week1
This week’s assignment we are going to solve two word problems. With both of these problems we will be working with proportions that both equal each other. These methods will require cross multiplication and division. After completing that I will find my answer with no variables.
My first equation is as follows: To estimate the size of the bear population on the Keweenaw Peninsula, conservationists captured, tagged, and released 50 bears. One year later, a random sample of 100 bears included only 2 tagged bears. What is the conservationist’s estimate of the size of the bear population?
I would write would write out this proportion as such:
x = 100 x over 50 equals 100 over 2, since I am trying to find out the rough
50 2 guesstimate of the bear population. From here I would cross multiply
the extreme to the mean, 50 by 100 and x by 2.
2x = 5,000 To get x by itself I will now divide 2 on one side and do the same to
the other side.
2x = 5,000
2 2
x = 2,500 My extraneous answer for bear population is 2,500.
My second equation is as follows:
y – 1 = -3 In order to solve for y...

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MAT 540 WEEK1 TO 11(Strayer)
MAT540 Week1 Homework
Chapter 1, Problems 2, 4, 12, 14, 20, 22
2. The Retread Tire Company recaps tires. The fixed annual cost of the recapping operation is $60,000.The variable cost of recapping a tire is $9.The company charges $25 to recap a tire.
a. For an annual volume of 12,000 tires, determine the total cost, total revenue, and profit.
b. Determine the annual break-even volume for the Retread Tire Company operation.
4. Evergreen Fertilizer Company produces fertilizer. The company’s fixed monthly cost is $25,000, and its variable cost per pound of fertilizer is $0.15. Evergreen sells the fertilizer for $0.40 per pound. Determine the monthly break-even volume for the company.
12. If Evergreen Fertilizer Company in Problem 4 changes the price of its fertilizer from $0.40 per pound to $0.60 per pound, what effect will the change have on the break-even volume?
14. If Evergreen Fertilizer Company increases its advertising expenditures by $14,000 per year, what effect will the increase have on the break-even volume computed in Problem 13?
Reference Problem 13: If Evergreen Fertilizer Company changes its production process to add a weed killer to the fertilizer in order to increase sales, the variable cost per pound will increase from $0.15 to $0.22. What effect will this change have on the break-even volume computed in...

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This paperwork MAT222Week 3 Discussion Questions 1 comprises solutions on the following tasks: Find the rational exponent problems assigned to you in the table below. Simplify each expression using the rules of exponents and examine the steps you are taking. Incorporate the following five math vocabulary words into your discussion. Use bold font to emphasize the words in your writing (Do not write definitions for the words; use them appropriately in sentences describing the thought behind your math work.): - Principal root - Product rule - Quotient rule - Reciprocal - nth root
Mathematics - Algebra
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MAT222MAT/222 MAT222 Algebra
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When during initial meetings the manager elicits the attention and the respect of all the employees, by explaining the objectives that should be reached within a time frame mainly selling a number of products within a set time frame and try to attract clients namely in the range of hundred a week. The manager appreciates the talents of the employees and tells them so specifically; “I know that you can succeed; I have full trust in all of you. However in case you need clarification or information or direction I am at your full disposal whenever you feel you want to contact me, all of you have been duly trained and I have been through your personal files and know that you can make it, so we can start as from today”. Frank two-way discussions between the manager and the employees will do away with any pent-up feelings and employees will relish the opportunity to provide their verbal contributions. This informal opportunity to disseminate and accumulate information will be the right forum to avail oneself of the entire information possible, do away with misinformation and disintegrate prejudices. Every week an analysis is carried out by the manager to check whether the objectives have been reached or whether new adjustments have to be made or maybe change the benchmark in so doing the manager has the ability to know where he stands for future reference and adapts the approaches for his personnel...

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This work MAT222Week 5 Discussion Questions 1 Relations and Functions contains solutions on the following tasks: Find your two equations in the list below based on the last letter of your last name. There are many ways to go about solving math problems. For this assignment you will be required to do some work that will not be included in the discussion. First, you need to graph your functions so you can clearly describe the graphs in your discussion. Your graph itself is not required in your post, although the discussion of the graph is required. Make sure you have at least five points for each equation to graph. Show all math work for finding the points. Specifically mention any key points on the graphs, including intercepts, vertex, or start/end points. (Points with decimal values need not be listed, as they might be found in a square root function. Stick to integer value points.) Discuss the general shape and location of each of your graphs. State the domain and range for each of your equations. Write them in interval notation. State whether each of the equations is a function or not giving your reasons for the answer. Select one of your graphs and assume it has been shifted three units upward and four units to the left. Discuss how this transformation affects the equation by rewriting the equation to incorporate those numbers. Incorporate the following five math vocabulary words into your...

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Simplifying Expressions
MAT 221
2a (a – 5) + 4(a – 5)
2a (a – 5) + 4(a – 5) Problem which was given
2a (a) – 2a (5) + 4(a) + 4(5) to the left Distributive Property of Addition over Multiplication
2(a a) – 2a (5) + 4(a) + 4(5) and the Associative Property of Multiplication
2(a a) – 2(5) a + 4(a) + 4(5) and the Commutative Property of Multiplication
2(a a) – (2*5) a + 4(a) + 4(5) and the Associative Property of Multiplication
2a2 – 10a + 4a + and the 20 Multiplication Properties
2a2 – 6 a + 20 and the Subtraction Property
Now on the left hand side is a step of the mathematical reasoning for 2a (a – 5) + 4(a – 5) to be simplified as 2a2 – 6a + 20. Also on the right hand side are the steps for logical reasoning. Now the middle part I used a combined because of the terms are like and the extreme terms are unlike any of the other three terms. Now the parentheses are used to show that the associative property and removed from and the multiplication and subtraction. Although the numerical coefficient must come before the literal coefficient of the problem.
2w – 3 + 3(w – 4) – 5(w – 6)
2w – 3 + 3(w – 4) – 5(w – 6) the given problem are on the
2w – 3 + 3w + 3(-4) + (-5) w + (-5)(-6) left side of the Distributive Property of Addition over the Multiplication
2w + 3w – 3 + 3(-4) + (-5) w + (-5)(-6) and the Commutative Property of Addition
2w +...