Describe the transformations on the following graph of f ( x) log( x) . State the placement of the vertical asymptote and x-intercept after the transformation. For example, vertical shift up 2 or reflected about the x-axis are descriptions. 1)

Description of transformation: Equation(s) for the Vertical Asymptote(s): x-intercept in (x, y) form: b) g ( x) log( x) 2

Description of transformation: Equation(s) for the Vertical Asymptote(s): x-intercept in (x, y) form:

2) Students in an English class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. The average score S(t), in percent, after t months was found to be given by S(t) = 68 − 20 log (t + 1), t ≥ 0. a) What was the average score when they initially took the test, t = 0?

Answer: Show your work in this space: b) What was the average score after 14 months?

Answer:

Show your work in this space:

c) After what time t was the average score 40%? Answer: Show your work in this space:

3) The formula for calculating the amount of money returned for an initial deposit into a bank account or CD (certificate of deposit) is given by r A P1 n A is the amount of the return. P is the principal amount initially deposited. r is the annual interest rate (expressed as a decimal). n is the number of compound periods in one year. t is the number of years. nt

Carry all calculations to six decimals on each intermediate step, then round the final answer to the nearest cent.

Suppose you deposit $3,000 for 6 years at a rate of 7%. a) Calculate the return (A) if the bank compounds semi-annually. Round your answer to the nearest cent. Answer:

Show work in this space. Use ^ to indicate the power or use the Equation Editor in MS Word.

...Answer Form Unit5 IP_2
April 22, 2011
(1.)
a.
e^(0.05t)=1600
Answer: t=147.556
Show your work:
ln(e^(0.05t))=ln(1600)
0.05t=ln(1600)
(0.05t)/(0.05)=(ln(1600))/(0.05)
t=(ln(1600))/(0.05)
t=20ln(1600)
t=147.556
b.
ln(4x)=3
Answer: x= 5.0214
Show your work:
4x = e^3/4
c.
log2(8-6x) = 5
Answer: x= -4
Show work:
8 – 6x = 2^5
6x = 8 – 32
X = - 24/6
d.
4 + 5e – x = 0
Answer: no solution found
Show work:
e ^ - x = - 4/5
(2.)
a.
g(x) = log (x + 5)
Description of transformation: shifted left 5units
Equation for vertical asymptote: x = -5
X-intercept in (x, y) form: (- 4, 0)
b.
g(x) = log ( - x)
Description of transformation: no units were moved, stayed in same place
Equation for vertical asymptote: x = 0
X-intercept in (x, y) form: (-1, 0)
(3.)
a.
Answer: 68 %
Show work:
S (0) = 68 – 20 * log (0 + 1)
S (0) = 68 – 20 * 0 = 68
b.
Answer:
After 4 months:
54.02%
After 24 months:
40.04%
Show work:
S (4) = 68 – 20 * log (4 + 1) = 54.02
S (24) = 68 – 20 * log (24 + 1) = 40.04
c.
Answer: t = 6.94
Show work:
50 = 68 – 20 log ( t + 1)
t + 1 = 10 ^ (18 / 20) = 7.9433
t= 7.9433 – 1 = 6.94
(4.)
a.
Answer: A= $2,938.66
Show work:
A= 2000 * (1+ 0.08/1) ^ (1*5) = 2938.66
b.
Answer: A=...

...Student Answer form Unit 2
1.
a. x-4x=-6
A) 1
B) -10
C) -6
X^2-10x-24=0
(X-4) (x+6)
X-4=0 x=4
X+6=0 x+-6
b. x=7+4=5.5 x=7-4=1.5
x=-b±b2-4ac2a
x= (-7) ± (-7)2-4(3) (20)2a
x=7±64-802a
x=7±-16
x=7+4/2=5.5
x=7-4/2=1.5
c. 10x^2+x-3=0
x=-b±b2-4ac2a
x=-1± (1)2-4(10) (-3)2(10)
x=1±1-12020
x=1±10
x=1+320 = 5
x=1-320= 10
2.
a. (-2.3, 0), (0, 6.3)
b. This is a maximum function.
This is a maximum function because it is at the peak of the parabola.
c. (2, 9)
d. x=2
3.
a. s= -16t^2+64t+25
b. 73 Feet
S= -16◦(1)^2+64◦(1)+25
S= -16+64+25
S=73 feet
c. 2 seconds
-b2a= -642(-16)= -64/-32=2 seconds
d. 89 feet
S= -16*(2)^2+64*(2)+25
S= 64+128+25= 89 feet
4.
a. x | y |
-2 | 4 |
-1 | 0 |
0 | -2 |
1 | -2 |
2 | 0 |
3 | 4 |
Y=x^2-x-2
X=-2 x= -1 x=0 x=1
Y=-2^2-(-2)-2 y= -1^2-(-1)-2 y= 0^2-0-2 y=1^2-1-2
Y=4+2-2 y= 1+1 -2 y= -2 y= 1-1-2
Y=6-2 y= 2-2 y= 0-2
Y=4 y=0...

...Claude Monet, who was born by the name of Oscar Claude Monet was born on November 14, 1840 in Paris France. He took his easel to the St Lazare railroad station and painted his painting in the train shed. He was amongst the famous French painters who started the Impressionism art movement. He began to love drawing in his early ages, he was known around town for painting the residents, he started exploring the world after he met a local landscape artist by the name of Eugene Boudin, he was introduced to outdoor painting which became is cornerstone work. He became a student at the Le Havre College. Claude was inspired to paint by the artist Edouard Manet. In 1923 Claude was nearly blind but had surgery to fix his sight, he later died on December 5, 1926 at the age of 86 from lung cancer.
”Two Young Girls At the Piano”
Renoir was invited by the French government to execute a painting for a new museum in Paris, the Musée du Luxembourg, which was to be devoted to the work of living artists. He chose his painting of the two girls at the piano. Renoir was born on February 25, 1841 in Limoges France, he was a French painter and also amongst the Impressionism art movement. When he was nine years old his older sister introduced him to painting. He was enrolled in the academically oriented studio of Charles Glerye in 1862. While attending the studio, he met other artists like Claude Monet, Alfred Sisley and Federic Bazelle. After he left the studio he painted with...

...unable to go into teaching. After a few years I decided to take up employment in a private nursery. When going for interview I was frequently told I was over qualified for the position of Nursery Nurse as a level 2 or 3 NVQ is the qualification required for this position.
Eventually I was employed in the private sector, where I have worked ever since. I am currently employed as the nursery teacher in the pre-school room. I feel that I am able to pass on my knowledge to the other practitioners in the setting, which in turn helps them to improve their practice.
I am now at the stage in my life where I feel that I would like to move out of the rooms and work on the management side. Therefore I have decided to retrain by completing this level 5 qualification to enable me to improve my knowledge of the management of a nursery setting, and to become a competent Deputy Manager.
3.Be able to prepare a professional development plan
3.1 – Select learning opportunities to meet development objectives and reflect personal learning style
There are three different learning styles. Auditory, whereby the learner is able to listen to explanations. Visual, where the learning takes place by looking at graphics, watching demonstrations or reading, and finally Kinestheic, where the learner processes the information through a hands on experience, by doing the activity, or writing notes to help them to understand.
Most learners use a combination of all 3 styles, but have a clear...

...Tystiolaeth Cyflawniad/Performance evidence record
Uned/Unit 520
Enw’r ymgeisydd/Candidate name Heather Mann
Defnyddiwch y ffurflen hon I gyfnodi manylion gweithgareddau (Ticiwch y bwlch priodol)
Use this form to record details of activities (tick appropriate box)
Arsyllwyd gan eich asesydd
Observed by your assessor
Gwelwyd gan arbenigwr tyst
Seen by an expert witness
Adroddiad huan adlewyrchol
Self reflective account
CD –Canlyniad Dysgu
LO – Learner Outcome
SYLWER Gall eich asesydd ofyn cwestiynau llafar yn berthynas i’r gweithgaredd hon. Sicrhau eu bod yn cael eu cofnodi yn y bocs priodol. Bydd rhaid i’r person sydd wedi ardystio/arsylwi arwyddo y dudalen olaf
NB Your assessor may wish to ask you some questions relating to this activity. Ensure they are either recorded in the performance evidence or on a “Questioning record. The person who observed/witnessed your activity must sign and date the last page.
Dyddiad y gweithgaredd
Date of activity
Uned
Unit
CD
LO
Tystiolaeth y perfformiad
Performance evidence
Good staff are the key point to a successful business. They need to be the right person for the right role. A poor staff member can cost time and money and can in turn bring a lack of confidence in the Company by the authorities which use our services. IT is therefore imperative that the recruitment criteria to followed and adhered to.
We have a recruitment and selection policy ( see...

...MATH133 UNIT 2: Quadratic Equations
Individual Project Assignment: Version 2A
Show all of your work details for these calculations. Please review this Web site to see how to
type mathematics using the keyboard symbols.
Problem 1: Modeling Profit for a Business
IMPORTANT: See Question 3 below for special IP instructions. This is mandatory.
Remember that the standard form for the quadratic function equation is y = f (x) = ax2 + bx + c
and the vertex form is y = f (x) = a(x – h)2 + k, where (h, k) are the coordinates of the vertex of
this quadratic function’s graph.
You will use P(x) = −0.2x2 + bx – c where (−0.2x2 + bx) represents the business’ variable profit
and c is the business’s fixed costs.
So, P(x) is the store’s total annual profit (in $1,000) based on the number of items sold, x.
1. Choose a value between 100 and 200 for b. That value does not have to be a whole
number.
2. Think about and list what the fixed costs might represent for your fictitious business (be
creative). Start by choosing a fixed cost, c, between $5,000 and $10,000, according to the
first letter of your last name from the values listed in the following chart:
If your last name begins with the letter
Choose a fixed cost between
A–E
$5,000–$5,700
F–I
$5,800–$6,400
J–L
$6,500–$7,100
M–O
$7,200–$7,800
P–R
$7,800–$8,500
S–T
$8,600–$9,200
U–Z
$9,300–$10,000
Page 1 of 4
3. Important: By Wednesday night at midnight, submit a Word document with...

...UNIT 4 INDEPENDENT PROJECT
NATALIE PORTMAN
Choosing Natalie Portman to write about was a no brainer for me because it isn’t everyday that you find such an accomplished actress with so many movies on her resume that also went to Harvard. Many people would agree that Portman is a fantastic actress with strong morals and beliefs.
Natalie was born on June 9th 1981 in Jerusalem, Israel as Natalie Hershlag. Her parents migrated to America when she was 3 and settled in Washington, later Connecticut and finally Long Island. Her first challenge came about around the time of her first onscreen debut when she was 11. Her grandfather was a Polish-Jew socialist and to avoid any judgment because of her affiliation with that group she took her grandmothers last name, Portman. Being a famous young actress trying to blend in with her fellow peers also posed a challenge for her, she told Premier (1995) that she thought school was much harder than real life, and that people are so much more accepting when they are adults. The negativity from her peers only drove her to be a better person and to only pick movie roles that portrayed a positive role model for young girls.
Education was always Portman’s main focus, not only throughout her career as an actress but throughout her life also. Whether she was studying acting at Usdan Theatre Art Camp, ballet, tap dancing, and jazz classes or attending regular grade school she always knew school came first. In 1994 Portman told...

...2750185165036500-575310165036500inclined plane with pulley and weights.
The first part of the experiment is “Determination of the Coefficient of Friction” as shown in Figure 5. The first procedure is to position the wooden plane horizontally then measure the weights of the block and pan using the platform balance. Next is to tie one end of the string to the block’s hook and the other end to the pan passing over the pulley of the plane. Next, place the narrow side of the block on top of the plane. Next, slowly add weights on the pan until you observe a uniform sliding motion of the block along the plane. Record the weights on the 3735070000data sheet then repeat it by adding smaller weights on top of the block and adjusting the weights on the pan. Make five (5) trials but on the third trial, use the wide side of the block. Calculate µ for each trial and finally 37357053016250Figure 5. Set Up for the Determination of the Coefficient of the Friction
0Figure 5. Set Up for the Determination of the Coefficient of the Friction
determine its average value. Lastly, Plot Wb along the abscissa (x-axis) and Wp along the ordinate (y-axis). Get the slope of the line.
Table 1. Determination if the Coefficient Friction
TRIAL (Wblock + Weightadded)
Wb(Wpan + Weightadded)
WpCoefficient Friction
µ
1 138.9 g 30 g 0.22
2 238.9 g 40 g 0.17
3 138.9 g 30 g 0.22
4 238.9 g 85 g 0.36
5 338.9 g 105 g 0.31...

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